Steinberg homology, modular forms, and real quadratic fields

JOURNAL OF NUMBER THEORY

卷:224

Article

Ash, Avner¹  Yasaki, Dan² 

[1] Boston Coll, Chestnut Hill, MA 02467 USA

[2] UNCG, Greensboro, NC 27412 USA

关键词: Arithmetic homology;    Steinberg representation;    Real quadratic field;    General linear group;    Arithmetic group;    Modular form;   

DOI  :  10.1016/j.jnt.2020.12.014

来源: Elsevier

【 摘 要 】

We compare the homology of a congruence subgroup ? of GL2(Z) with coefficients in the Steinberg modules over Q and over E, where E is a real quadratic field. If R is any commutative base ring, the last connecting homomorphism ??,E in the long exact sequence of homology stemming from this comparison has image in H0(?, St(Q2; R)) generated by classes z? indexed by ? ? E \ Q. We investigate this image. When R = C, H0(?, St(Q2; C)) is isomorphic to a space of classical modular forms of weight 2, and the image lies inside the cuspidal part. In this case, z? is closely related to periods of modular forms over the geodesic in the upper half plane from ? to its conjugate ?'. Assuming GRH we prove that the image of ??,E equals the entire cuspidal part. When R = Z, we have an integral version of the situation. We define the cuspidal part of the Steinberg homology, Hcusp 0 (?, St(Q2; Z)). Assuming GRH we prove that for any congruence subgroup, ??,E always has finite index in Hcusp 0 (?, St(Q2; Z)), and if ? = ?1(N)? or ?1(N), then the image is all of Hcusp 0 (?, St(Q2; Z)). If ? = ?0(N)? or ?0(N), we prove (still assuming GRH) an upper bound for the size of Hcusp 0 (?, St(Q2; Z))/ Im(??,E). We conjecture that the results in this paragraph are true unconditionally. We also report on extensive computations of the image of ??,E that we made for ? = ?0(N)? and ? = ?0(N). Based on these computations, we believe that the image of psi gamma,E is not all of Hcusp 0 (gamma, St(Q2; Z)) for these groups, for general N. (c) 2021 Elsevier Inc. All rights reserved.

【 授权许可】

Free