期刊论文详细信息
Crux mathematicorum with mathematical mayhem | |
Contest Corner Solutions: CC331–CC340 | |
1  | |
DOI : | |
学科分类:数学(综合) | |
来源: Canadian Mathematical Society | |
【 摘 要 】
Consider triangle ABC with \B = \C = 70 . On the sides ABand AC, we take the points F and E, respectively, so that \ABE = 15and\ACF = 30 . Find \AEF.Originally 2016 BC Exam, Texas A&M High School Math Contest, #20.We received 12 correct solutions. We present the solution by Ivko Dimitri c.
【 授权许可】
CC BY
【 预 览 】
Files | Size | Format | View |
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RO201910280327359ZK.pdf | 277KB | download |