Contest Corner Solutions: CC331–CC340

Crux mathematicorum with mathematical mayhem

¹ 

DOI  :  

学科分类：数学（综合）

来源: Canadian Mathematical Society

【 摘 要 】

Consider triangle ABC with \B = \C = 70 . On the sides ABand AC, we take the points F and E, respectively, so that \ABE = 15and\ACF = 30 . Find \AEF.Originally 2016 BC Exam, Texas A&M High School Math Contest, #20.We received 12 correct solutions. We present the solution by Ivko Dimitri c.

【 授权许可】

CC BY